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x^2+800x+80000=0
a = 1; b = 800; c = +80000;
Δ = b2-4ac
Δ = 8002-4·1·80000
Δ = 320000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{320000}=\sqrt{160000*2}=\sqrt{160000}*\sqrt{2}=400\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(800)-400\sqrt{2}}{2*1}=\frac{-800-400\sqrt{2}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(800)+400\sqrt{2}}{2*1}=\frac{-800+400\sqrt{2}}{2} $
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